Answer
a). $0.72 m/s^{2}$
b). $281.5N$
Work Step by Step
a). From Newton's second law,
$Fcos\theta=ma$, $\theta=30^{\circ}$
$a=\frac{Fcos\theta}{m}=\frac{25\times0.866}{30}=0.72m/s^{2}$
b). Normal force = $w-Fsin\theta=30\times9.8-12.5=281.5N$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 40
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