Answer
a). $0.96m/s^{2}$
b). $263.1N$
Work Step by Step
a). $a=\frac{Fcos\theta}{m}=\frac{30cos37^{\circ}}{25}=0.96m/s^{2}$
b). Normal force =$w+Fsin\theta=25\times9.8+30sin37^{\circ}=263.1N$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 41
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