Answer
a). (2) two forces,
b). $5.9m/s^{2}$,
c). $20.9m/s$
Work Step by Step
a). Two forces act on the skier - the weight , mg and the normal force N.
b). $w_{x}=mgsin\theta$
$a=\frac{mgsin\theta}{m}=gsin\theta=9.8sin37^{\circ}=5.9m/s^{2}$
c). $v^{2}=u^{2}+2aS=5^{2}+2\times 5.9\times 35$
$v=20.9m/s$