Answer
The tensions beginning from upper most wires are 69N each, 20N for wire AB, 57N each, and 98N.
Work Step by Step
For part of below most wire, $T_{2}=\frac{mg}{2cos30^{\circ}}=\frac{10\times9.8}{2cos30^{\circ}}=57N$
For upper most part, $T_{1}=\frac{mg}{sin45^{\circ}}=69N$
$T_{AB}=69cos45^{\circ}-57sin30^{\circ}=20N$
And finally $T=mg=98N$