College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 42

Answer

a). $0.71m/s^{2}$ b). $1065N$

Work Step by Step

a). $a=\frac{F}{m}=\frac{3200}{3000+1500}=0.71m/s^{2}$ b). $F=ma=1500\times 0.71=1065N$
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