College Physics (7th Edition)

by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo

Published by Pearson

ISBN 10: 0-32160-183-1

ISBN 13: 978-0-32160-183-4

Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 45

Answer

$63.8m$

Work Step by Step

Acceleration due to gravity parallel to the surface $=gsin30^{\circ}=0.5g$ $v^{2}=u^{2}+2aS$ $0=25^{2}-2\times0.5gS$ $S=\frac{25\times25}{9.8}=63.8m$

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