Answer
$63.8m$
Work Step by Step
Acceleration due to gravity parallel to the surface $=gsin30^{\circ}=0.5g$
$v^{2}=u^{2}+2aS$
$0=25^{2}-2\times0.5gS$
$S=\frac{25\times25}{9.8}=63.8m$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 45
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