Answer
$2.626m/s^{2}$
Work Step by Step
$Tsin15^{\circ}=ma$
$Tcos15^{\circ}=mg$
Therefore, from above 2 equations, $tan15^{\circ}=\frac{a}{g}$
$a=gtan15^{\circ}=2.626m/s^{2}$
College Physics (7th Edition)
by Wilson, Jerry D.; Buffa, Anthony J.; Lou, Bo
Published by
Pearson
ISBN 10:
0-32160-183-1
ISBN 13:
978-0-32160-183-4
Chapter 4 - Force and Motion - Learning Path Questions and Exercises - Exercises - Page 137: 49
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