Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-6 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 46: 27

Answer

$-2\lt x \lt 6$ Refer to the graph below.

Work Step by Step

Using the properties of inequality, the given, $ |3x-6|+3\lt15 ,$ is equivalent to \begin{align*}\require{cancel} |3x-6|+3-3&\lt15-3 \\ |3x-6|&\lt12 .\end{align*} Since for any $c\gt0$, $|x|\lt c$ implies $-c\lt x\lt c$ (or $|x|\le c$ implies $-c\le x\le c$), the inequality above implies \begin{align*}\require{cancel} -12\lt 3x-6 &\lt12 .\end{align*} Using the properties of inequality, the inequality above is equivalent to \begin{align*}\require{cancel} -12+6\lt 3x-6+6 &\lt12+6 \\ -6\lt 3x &\lt 18 \\\\ -\dfrac{6}{3}\lt \dfrac{3x}{3} &\lt \dfrac{18}{3} \\\\ -2\lt x &\lt 6 .\end{align*} Hence, the solution is $ -2\lt x \lt 6 .$ Since a hollowed dot is used for the symbols $\lt$ and $\gt,$ while a solid dot is used for the symbols $\le$ and $\ge,$ then the graph of the solution above is the set of numbers from $ -2 $ to $ 6 $ with hollowed dots at $ -2 $ and $ 6 $.
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