Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-6 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 46: 38

Answer

$|k-50.5|\le0.5$

Work Step by Step

Half-way between the given values, $ 50\text{ and } 51 ,$ is \begin{array}{l}\require{cancel} \dfrac{50+51}{2} \\\\= \dfrac{101}{2} \\\\= 50.5 .\end{array} The distance from $ 50.5 $ to $50$ and $51$ is $ 0.5 .$ Since $|x|\lt c$ implies $-c\lt x\lt c$ (or $|x|\le c$ implies $-c\le x\le c$), then the given inequality, $ 50\le k \le51 ,$ is equivalent to \begin{array}{l}\require{cancel} |k-50.5|\le0.5 .\end{array}
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