Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 1 - Expressions, Equations, and Inequalities - 1-6 Absolute Value Equations and Inequalities - Practice and Problem-Solving Exercises - Page 46: 41

Answer

$|m-1250|\le50$

Work Step by Step

Half-way between the given values, $ 1200\text{ and } 1300 ,$ is \begin{array}{l}\require{cancel} \dfrac{1200+1300}{2} \\\\= \dfrac{2500}{2} \\\\= 1250 .\end{array} The distance from $ 1250 $ to $1200$ and $1300$ is $ 50 .$ Since $|x|\lt c$ implies $-c\lt x\lt c$ (or $|x|\le c$ implies $-c\le x\le c$), then the given inequality, $ 1200\le m \le1300 ,$ is equivalent to \begin{array}{l}\require{cancel} |m-1250|\le50 .\end{array}
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