Answer
$\frac{x-1}{x+3}$
Work Step by Step
$\frac{x^2+4x-5}{x^2+8x+15}=\frac{(x+5)(x-1)}{(x+5)(x+3)}=\frac{x-1}{x+3}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 25
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