Answer
$\frac{(t-3)}{(t+3)(t-2)}$
Work Step by Step
$\frac{t^2-t-6}{t^2+6t+9}\frac{t+3}{t^2-4}=\frac{(t+2)(t-3)}{(t+3)^2}\frac{t+3}{(t+2)(t-2)}=\frac{(t+2)(t-3)(t+3)}{(t+3)^2(t+2)(t-2)}=\frac{(t-3)}{(t+3)(t-2)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 36
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
