Answer
$\frac{(x-y)}{x(x+y)(x+y)}$
Work Step by Step
$\frac{x^2+xy-2y^2}{x^3+x^2y}\frac{x}{x^2+3xy+2y^2}=\frac{(x+2y)(x-y)}{x^2(x+y)}\frac{x}{(x+y)(x+2y)}=\frac{(x+2y)(x-y)x}{x^2(x+y)(x+y)(x+2y)}=\frac{(x-y)}{x(x+y)(x+y)}$
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