Answer
$\frac{x}{x+3}$
Work Step by Step
Both fractions have the same denominator:
$\frac{2x-1}{x+3}+\frac{1-x}{x+3}=\frac{(2x-1)+(1-x)}{x+3}=\frac{2x-1+1-x}{x+3}=\frac{x}{x+3}$
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