Answer
$\frac{1}{5x-10}$
Work Step by Step
$\frac{5}{x-1}.\frac{x-1}{25(x-2)}=\frac{5(x-1)}{(x-1)(25)(x-2)}$
Eliminate (x-1) in both numerator and denominator:
$\frac{5}{(25)(x-2)}=\frac{5}{5(5)(x-2)}=\frac{1}{5(x-2)}=\frac{1}{5x-10}$
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