Answer
$\frac{x^2-7x-24}{(x+4)(x-1)}$
Work Step by Step
$\frac{x}{x+4}-\frac{6}{x-1}=\frac{x(x-1)}{(x+4)(x-1)}-\frac{6(x+4)}{(x+4)(x-1)}=\frac{x(x-1)-6(x+4)}{(x+4)(x-1)}=\frac{x^2-x-6x-24}{(x+4)(x-1)}=\frac{x^2-7x-24}{(x+4)(x-1)}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 42
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