Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 35

Answer

$\frac{(x+2)^2}{6}$, with $x\ne2$

Work Step by Step

$\frac{x^2-4}{12}\div\frac{2-x}{2x+4}=\frac{x^2-4}{12}\frac{2x+4}{x-2}=\frac{(x+2)(x-2)}{2(6)}\frac{2(x+2)}{x-2}=\frac{(x+2)^2}{6}$
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