Answer
$-\dfrac{1}{16}$
Work Step by Step
The given expression is equivalent to
$-(4^{-2})$
RECALL:
$a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use the rule above to obtain:
$-(4^{-2}) = -(\dfrac{1}{4^2})=-(\dfrac{1}{16})=-\dfrac{1}{16}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 78
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