Answer
$-\dfrac{1}{4x^2}$
Work Step by Step
RECALL:
(1) $(a^m)^n=a^{mn}$
(2) $(ab)^m=a^mb^m$
(3) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
(4) $a^1 = a$
Use rule (3) above to obtain:
$=\dfrac{1}{(-4x^2)^1}$
Use rule (4) above to obtain:
$=\dfrac{1}{-4x^2}
\\=-\dfrac{1}{4x^2}$
