Answer
$4$
Work Step by Step
RECALL:
(1) $a^m \cdot a^n = a^{m+n}$
(2) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use rule (1) above to obtain:
$=4^{-2+3}
\\=4^{1}
\\=4$
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