Answer
$\displaystyle \frac{1}{x^{3}y}$
Work Step by Step
We simplify:
$\displaystyle \frac{x^{-2}y^1}{xy^{2}}=x^{-2-1}y^{1-2}=x^{-3}y^{-1}=\frac{1}{x^{3}y}$
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