Answer
$\displaystyle \frac{216x^{6}}{125y^{6}}$
Work Step by Step
We simplify:
$(\displaystyle \frac{5x^{-2}}{6y^{-2}})^{-3}
=(\frac{5y^{2}}{6x^{2}})^{-3}
=(\frac{6x^{2}}{5y^{2}})^{3}
=\frac{6^{3}(x^{2})^{3}}{5^{3}(y^{2})^{3}}
=\frac{216x^{6}}{125y^{6}}$