Answer
$8$
Work Step by Step
RECALL:
(1) $a^m \cdot a^n = a^{m+n}$
(2) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
(3) $(a^{m})^{n}=a^{mn}$
Use rule (3) above to obtain:
$=2^{(-1)(-3)}
\\=2^{3}
\\=2(2)(2)
\\=8$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 82
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