Answer
-3
Work Step by Step
$g'(t)=\lim\limits_{h \to 0}\frac{g(t+h)-g(t)}{h}=\lim\limits_{h \to 0}\frac{[8-3(t+h)]-[8-3t]}{h}$
$=\lim\limits_{h \to 0}\frac{8-3t-3h-8+3t}{h}=-3$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 3 - Differentiation - 3.1 Definition of the Derivative - Exercises - Page 103: 19
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