Answer
all real x, $x\ne-3, 3$
Work Step by Step
The function is defined for all real x where the denominator $x^{2}-9\ne0$.
When $x^{2}-9=0, x=\pm\sqrt 9=\pm3$
Therefore, x=-3, 3 are excluded from the domain.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 31
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