Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 47

Answer

The graph for function $g(t) = |1 - 3t|$

Work Step by Step

$g(t) = |1 - 3t|$ $g(-2) = |1 - 3(-2)|$ ⇒ $g(-2) = 7$ $g(-1) = |1 - 3(-1)|$ ⇒ $g(-1) = 4$ $g(-\frac{1}{3}) = |1 - 3(-\frac{1}{3})|$ ⇒ $g(-\frac{1}{3}) = 2$ $g(0) = |1 - 3(0)|$ ⇒ $g(0) = 1$ $g(\frac{1}{3}) = |1 - 3(\frac{1}{3})|$ ⇒ $g(\frac{1}{3}) = 0$ $g(1) = |1 - 3(1)|$ ⇒ $g(1) = 2$ $g(2) = |1 - 3(2)|$ ⇒ $g(2) = 5$ Plot the set of points: $(-2,7)$, $(-1,4)$, $(-\frac{1}{3},2)$, $(0,1)$, $(\frac{1}{3},0)$, $(1,2)$, $(2,5)$.
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