Answer
all real x, $x\ne-3,2$
Work Step by Step
$f(x)$ is defined for all real x where the denominator $x^{2}+x-6\ne0$.
When $x^{2}+x-6=(x+3)(x-2)=0, x=-3,2$
Therefore, $x=-3,2$ are excluded from the domain.
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 32
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