Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 44

Answer

As a result $f(-3)=-1, f(0)=-1, f(2)=3$.

Work Step by Step

$f(x)=-1$ for $x\leq1$ and $f(x)=7-2x$ for $x\gt1$ $f(-3)=-1\Rightarrow f(-3)=-1$ $f(0)=-1\Rightarrow f(0)=-1$ $f(2)=7-2(2)\Rightarrow f(2)=3$
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