Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 52

Answer

$y=-\frac{5}{3}x+\frac{5}{3}$

Work Step by Step

The equation of a line which connects two points is $y-y_{1}= m(x-x_{1})$ where $m=\frac{y_{2}−y_{1}}{x_{2}−x_{1}}$ Our points are: $P_{1}$=(-5,10) $P_{2}$=(7,-10) Substituting our points we get $m=\frac{-10-10}{7-(-5)}=-\frac{5}{3} $ $y-10=-\frac{5}{3}(x-(-5))$ $y=-\frac{5}{3}x+\frac{5}{3}$
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