Answer
all real $t$
Work Step by Step
$\because 2t-1$ is real and defined for all real $t$, and the cube root of a real number is still a real number
$\therefore \sqrt[3] (2t-1)$ is defined for all real $t$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 21: 33
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