Answer
$\frac{2x^{2}-1}{x-2}$
Work Step by Step
$\frac{2}{\frac{x-2}{x^{2}}}-\frac{1}{x-2}=\frac{2x^{2}}{x-2}-\frac{1}{x-2}=\frac{2x^{2}-1}{x-2}$
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