Answer
$\displaystyle \frac{2x-3}{x^{2}y}$
Work Step by Step
We first add the two fractions in the brackets,
common denominator : xy
$=\displaystyle \frac{1}{x}\cdot\frac{x-3+1\cdot x}{xy}=\frac{1}{x}\cdot\frac{x-3+x}{xy}$
$=\displaystyle \frac{1}{x}\cdot\frac{2x-3}{xy}$
Multiplying fractions:
$=\displaystyle \frac{1\cdot(2x-3)}{x\cdot xy}$
$=\displaystyle \frac{2x-3}{x^{2}y}$
