Answer
$$\frac{y^7}{x^8}$$
Work Step by Step
\begin{align}
\frac{(xy^{-2})^{-2}}{(x^{-2}y)^{-3}} & = \frac{x^{-2}y^4}{x^6y^{-3}}\\ &= \frac{y^3y^4}{x^2x^6} \\ &= \frac{y^7}{x^8}
\end{align}
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 108
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