Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 110

Answer

$$\frac{y}{9x^7z^7}$$

Work Step by Step

\begin{align} (3x^{-4}yz^{-7})(3x)^{-3} & =(3x^{-4}yz^{-7})( 3^{-3}x^{-3}) \\ &= 3^{-2}x^{-7}yz^{-7} \\ &= \frac{y}{9x^7z^7} \end{align}
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