Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 92

Answer

$$1.53 \times 10^{-11}$$

Work Step by Step

\begin{align} (5.1 \times 10^{-8})(3 \times 10^{-4}) & = (5.1 \times 3)(10^{-8} \times 10^{-4})\\ &= 15.3 \times 10^{-8-4} \\ &=15.3 \times 10^{-12} \\ &= 1.53 \times 10^{-11} \end{align}
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