Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 59

Answer

$\frac{y^{2}}{25x^{6}}$

Work Step by Step

Start with the given expression: $(\frac{5x^{3}}{y})^{-2}$ Use negative exponent rule to invert fraction: $(\frac{y}{5x^{3}})^{2}$ Remove the parentheses: $\frac{y^{2}}{5^{2}(x^{3})^{2}}$ Use power rule to simplify denominator: $\frac{y^{2}}{25x^{6}}$
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