Answer
$\frac{1}{x^{32}y^{40}z^{48}}$
Work Step by Step
$(\frac{x^{4}y^{5}z^{6}}{x^{-4}y^{-5}z^{-6}})^{-4}=((x^{4}y^{5}z^{6})(x^{4}y^{5}z^{6}))^{-4}=(x^{8}y^{10}z^{12})^{-4}=\frac{1}{(x^{8}y^{10}z^{12})^{4}}=\frac{1}{x^{32}y^{40}z^{48}}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 112
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