Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 91

Answer

$$1.22 \times 10^{-11}$$

Work Step by Step

\begin{align} (6.1 \times 10^{-8})(2 \times 10^{-4}) & = (6.1 \times 2)(10^{-8} \times 10^{-4})\\ &= 12.2 \times 10^{-8-4} \\ &=12.2 \times 10^{-12} \\ &= 1.22 \times 10^{-11} \end{align}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.