Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.2 - Exponents and Scientific Notation - Exercise Set - Page 30: 60

Answer

$\frac{y^{2}}{27x^{12}}$

Work Step by Step

Start with the given expression: $(\frac{3x^{4}}{y})^{-3}$ Use negative exponent rule to invert fraction: $(\frac{y}{3x^{4}})^{3}$ Remove the parentheses: $\frac{y^{3}}{3^{3}(x^{4})^{3}}$ Use power rule to simplify denominator: $\frac{y^{2}}{27x^{12}}$
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