Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 104

Answer

$(x+10)(x-10)^2$

Work Step by Step

Step 1. Factor each denominator completely $x^2-100=(x+10)(x-10)$ and $x^2-20x+100=(x-10)^2=(x-10)(x-10)$ Step 2. List all the factors of the first denominator $(x+10), (x-10)$ Step 3. Add to the list any additional factors in the second denominator; we need to add $(x-10)$ to the list. Step 4. The least common denominator is $LCD=(x+10)(x-10)(x-10)=(x+10)(x-10)^2$
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