Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 105

Answer

See explanations.

Work Step by Step

Method 1. Evaluate the numerator and the denominator separately: $\frac{3}{x}+\frac{2}{x^2}=\frac{3x+2}{x^2}$ and $\frac{1}{x^2}+\frac{2}{x}=\frac{1+2x}{x^2}$. Then combine the results with division to get $\frac{3x+2}{x^2}\div\frac{1+2x}{x^2}=\frac{3x+2}{x^2}\times\frac{x^2}{2x+1}=\frac{3x+2}{2x+1}$ Method 2. Multiply the numerator and the denominator by the least common denominator $LCD=x^2$, $\frac{\frac{3}{x}+\frac{2}{x^2}}{\frac{1}{x^2}+\frac{2}{x}}\times\frac{x^2}{x^2}=\frac{3x+2}{1+2x}$
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