Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 108

Answer

The required solution is $\frac{a\left( b+x \right)}{bx}$

Work Step by Step

We have the given expression $\frac{a}{x}+\frac{a}{b}=\frac{a}{x+b}$. The left side of the given expression is $\frac{a}{x}+\frac{a}{b}$ Simplify the above expression: $\begin{align} & \frac{a}{x}+\frac{a}{b}=\frac{a}{x}\times \frac{b}{b}+\frac{a}{b}\times \frac{x}{x} \\ & =\frac{ab}{xb}+\frac{ax}{bx} \\ & =\frac{ab+ax}{bx} \\ & =\frac{a\left( b+x \right)}{bx} \end{align}$ And the right side of the given expression is $\frac{a}{x+b}$ So, $\frac{a}{x}+\frac{a}{b}\ne \frac{a}{x+b}$ Thus, the correct form of the given equation is $\frac{a}{x}+\frac{a}{b}=$ $\frac{a\left( b+x \right)}{bx}$.
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