Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.6 - Rational Expressions - Exercise Set - Page 87: 111

Answer

Does not make sense.

Work Step by Step

When dividing a rational expression, we need to invert the divisor and then multiply it to the first expression $\frac{7x}{x+3}\div\frac{(x+3)^2}{x-5}=\frac{7x}{x+3}\times\frac{x-5}{(x+3)^2}=\frac{7x(x-5)}{(x+3)^3}$. Thus, the statement does not make sense.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.