Answer
The statement $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ is true at $x=6$.
Work Step by Step
Consider the equation, $2\left( x-3 \right)-17=13-3\left( x+2 \right)$
Now, substitute the value $x=6$ in the equation $2\left( x-3 \right)-17=13-3\left( x+2 \right)$
Therefore,
$\begin{align}
& 2\left( 6-3 \right)-17=13-3\left( 6+2 \right) \\
& 2\left( 3 \right)-17=13-3\left( 8 \right) \\
& 6-17=13-18 \\
& -11=-11
\end{align}$
Hence, the statement $2\left( x-3 \right)-17=13-3\left( x+2 \right)$ is true at $x=6$.
