Answer
$(x)^2+(y-2)^2=4$,
$x^2+y^2-4y=0$,
See graph.
Work Step by Step
Step 1. Based on the given data, we can write the standard form as $(x)^2+(y-2)^2=4$,
Step 2. The general form is $x^2+y^2-4y=0$,
Step 3. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter F - Foundations: A Prelude to Functions - Section F.4 Circles - F.4 Assess Your Understanding - Page 38: 13
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