Answer
(a). $(h,k)=(-2,2), r=3$.
(b). See graph.
(c). $(-2\pm\sqrt 5,0)$, $(0, 2\pm\sqrt 5)$.
Work Step by Step
(a). $x^2+y^2+4x-4y=1 \longrightarrow (x+2)^2+(y-2)^2=9$, thus $(h,k)=(-2,2), r=3$.
(b). See graph.
(c). For x-intercept(s), let $y=0$, we get $(-2\pm\sqrt 5,0)$. For y-intercept(s), let $x=0$, we get $(0, 2\pm\sqrt 5)$.