Answer
$(x+2)^2+(y-1)^2=16$,
$ x^2+y^2+4x-2y-11=0$,
See graph.
Work Step by Step
Step 1. Based on the given data, we can write the standard form as $(x+2)^2+(y-1)^2=16$,
Step 2. The general form is $x^2+y^2+4x-2y+4+1-16=0\longrightarrow x^2+y^2+4x-2y-11=0$,
Step 3. See graph.
