Answer
$(x-\frac{1}{2})^2+(y)^2=\frac{1}{4}$,
$ 4x^2+4y^2-4x-3=0$,
See graph.
Work Step by Step
Step 1. Based on the given data, we can write the standard form as $(x-\frac{1}{2})^2+(y)^2=\frac{1}{4}$,
Step 2. The general form is $(2x-1)^2+4(y)^2=4\longrightarrow 4x^2+4y^2-4x-3=0$,
Step 3. See graph.
