Answer
$(x+5)^2+(y+2)^2=49$,
$ x^2+y^2+10x+4y-20=0$,
See graph.
Work Step by Step
Step 1. Based on the given data, we can write the standard form as $(x+5)^2+(y+2)^2=49$,
Step 2. The general form is $x^2+y^2+10x+4y+25+4-49=0\longrightarrow x^2+y^2+10x+4y-20=0$,
Step 3. See graph.
