Answer
$\left\{-1,5\right\}$
Work Step by Step
Apply square root property by taking the square root of both sides:
$\sqrt{(x-2)^2}=\pm \sqrt{9}\\
x-2= \pm 3\\
x=2\pm 3$
Thus,
$x_1=2+3=5\\
x_2=2-3=-1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter F - Foundations: A Prelude to Functions - Section F.4 Circles - F.4 Assess Your Understanding - Page 38: 2
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